首页
登录
职称英语
[img]2022m10x/ct_ve01204002j_0040_221018[/img]A factory assembles Product X fro
[img]2022m10x/ct_ve01204002j_0040_221018[/img]A factory assembles Product X fro
游客
2025-02-27
31
管理
问题
A factory assembles Product X from three components,A,B,and C.One 0f each component is needed for each Product X and all three components must be available when assembly of each Product X starts.It takes two days to assemble one Product X. Assembly of each Product X starts at the beginning of one day and is finished at the end 0f the next day.The factory can work on at most five Product Xs at once. If components are available each day as shown in the table above,what is the largest number 0f Product Xs that can be assembled during the three days covered by the table?
选项
A、3
B、5
C、6
D、9
E、10
答案
B
解析
We will determine the largest number of Product Xs that can be assembled during all three days by considering separately the largest number that can be assembled if 0,1,2, or 3 Product X’s begin assembly on Monday.
0 Product X’s begin assembly on Monday: In this case, at most three Product Xs can begin assembly on Tuesday (because only three units of Component A are available on Wednesday), and hence at most 0 + 3 = 3 Product Xs could be assembled during the three days.
1 Product X begins assembly on Monday: In this case, at most three Product Xs can begin assembly on Tuesday (because only three units of Component A are available on Wednesday), and hence at most 1 + 3=4 Product Xs could be assembled during the three days.
2 Product X’s begin assembly on Monday: In this case, at most three Product X’s can begin assembly on Tuesday (because only three units of Component A are available on Wednesday), and hence at most 2 + 3 = 5 Product Xs could be assembled during the three days.
3 Product X’s begin assembly on Monday: In this case, at most two Product Xs can begin assembly on Tuesday (because the factory can work on at most five Product Xs at once), and hence at most 3 + 2 = 5 Product Xs could be assembled during the three days.
Therefore, the largest number of Product Xs that can be assembled during the three days is 5.
The correct answer is B.
转载请注明原文地址:https://www.tihaiku.com/zcyy/3974656.html
相关试题推荐
[img]2022m10x/ct_ve01204002j_0066_221018[/img]Eachentryinthemultiplication
[img]2022m10x/ct_ve01204002j_0040_221018[/img]AfactoryassemblesProductXfro
[img]2022m10x/ct_ve01204002j_0037_221018[/img]Thetableaboveshowsthepercent
[img]2022m10x/ct_ve01204002j_0036_221018[/img]Thefigureaboveshowssomeofth
[img]2022m10x/ct_ve01204002j_0034_221018[/img]Inthefigureabove,PQisadiame
[img]2022m10x/ct_ve01204002j_0027_221018[/img]Thefigureaboveshowsthedimens
[img]2022m10x/ct_ve01204002j_0025_221018[/img]Thefigureaboveshows2circles.
Foreachpositiveintegerk,letak=[img]2022m10x/ct_ve01204002j_0043_221018[/img
有一九宫格,第一行第一列是a,共有a,b,c三个元素,将a,b,c放入,问使每行每列都有a,b,c三个元素一共有多少种不同的排法?[img]2022m10x/
三条直线能够把一个圆的内部最多分成多少个没有重叠部分的区域?A、5B、6C、7D、8E、9C[img]2022m10x/ct_ve01203002j_
随机试题
Wherearetheytalking?[br][originaltext]W:Goodmorning,canIhelpyou?M:
Aftertheconcert,theclean-upcrewfoundtheground_____withpapers,bottlesand
直肠癌发病的相关因素包括A.高脂、高蛋白饮食 B.家族性息肉病 C.直肠腺瘤
下列关于炸药和雷管的说法正确的有()。A.雷管由于材料的不同,分为火雷管与电雷管
保险人对“责任免除”以外的任何风险造成的损害负承保责任,这类保险合同属于()。A
A.肾细胞癌 B.睾丸肿瘤 C.前列腺癌 D.膀胱移行细胞癌可出现精索静脉
Thedangertotheplanliesin______.A.
蛛网理论的假定前提条件是()。A.周期性商品需求量对价格缺乏弹性 B.供给量
关于建设工程合同变更,说法正确的是( )。A.一方当事人可以根据交易习惯直接变
新生儿寒冷损伤综合征的主要临床表现是A.呕吐和腹泻 B.皮肤凉硬、体温不升
最新回复
(
0
)