2. 职称英语
  3. Scientists have long been interested in how the deaf process signed languag

Scientists have long been interested in how the deaf process signed languag

游客2024-12-03  19
问题     Scientists have long been interested in how the deaf process
signed languages in the braia Understanding that activity could shed
light to whether the brain contains specialized structures for decoding【M1】______
linguistic patterns in general regardless how they are conveyed. A【M2】______
new study published in Tuesday’s issue of Proceedings of the National
Academy of Science suggests that the brain does have such wiring,
challenged the idea that speech and sound are vital for human【M3】______
language. Laura Ann Petitto and other researchers base their
conclusions on a series of experiments which involves 11 profoundly
deaf people and 10 hearing people. Earlier work had demonstrated that
deaf people were processing signed sentences used mostly their left【M4】______
hemispheres, just as hearing people parsing spoken language. But the【M5】______
new study found that in addition, both groups rely on identical brain
structures for similar tasks. The researchers were particularly stunned
by this activity in the brain of the deaf.
    The puzzled finding has led Petitto and Zatorre to propose that【M6】______
perhaps areas of the brain once viewing as devoted to sounds actually【M7】______
contain different types of cells that are capable of responding at the【M8】______
patterns of natural language in any form. "Such neural specialization
for aspects of language patterning appears to be neurally modifiable,【M9】______
as languages with radically different sensory modalities such as speech
and sign are processed at different brain sites", the authors write,【M10】______
"while, at the same time, the neural pathways for expressing and
perceiving natural language appear to be neurally highly modifiable." [br] 【M1】
选项
答案 to→on
解析 词汇错误。shed light on sth．是固定搭配，表示“使……清楚，使……明白地显示出来。”
转载请注明原文地址:https://www.tihaiku.com/zcyy/3871873.html
相关试题推荐
随机试题
最新回复(0)