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  3. Consider a probability experiment with events M, N, and L for which P(M) = 0.25,

Consider a probability experiment with events M, N, and L for which P(M) = 0.25,

游客2024-01-12  44
问题 Consider a probability experiment with events M, N, and L for which P(M) = 0.25, P (N) = 0.35, and P (L) = 0.80. Suppose that events M and N are mutually exclusive and events N and L are independent. What are the probabilities P (M or N) and P (N or L)?
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答案 0.60，0.87
解析 已知M和N互斥，即P(M and N)=0，P(M or N)=P(M)+P(N)-P(M and N)=0.25+0.35-0=0.60。已知N和L独立，则P(N and L)=P(N)×P(L)=0.35×0.80=0.28，P(N or L)=P(N)+P(L)-P(N and L)=0.35+0.80-0.28=0.87。
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