首页
登录
职称英语
In the study of functional syntax, Halliday defines his ______ as "the one to wh
In the study of functional syntax, Halliday defines his ______ as "the one to wh
游客
2023-12-15
30
管理
问题
In the study of functional syntax, Halliday defines his ______ as "the one to whom or for whom the process is said to take place", which is also called Recipient in material processes, Client in verbal processes or Receiver in relational processes.
选项
A、range
B、circumstances
C、beneficiary
D、token
答案
C
解析
本题考查语言学概念。在对句子的研究中,澳大利亚语言学家韩礼德(Halliday)提出了系统功能语法的理论,指出语言元素组成系统。他认为我们对经验的印象是它由一些“事态”和“过程”组成。 Halliday区分了六个过程:物质过程(material)、心理过程(mental)、关系过程(relational)、行为过程 (behaviorial)、言语过程(verbal)和存在过程(existential)。题干中问到的相当于“物质过程”的“接受者”、“言语过程”的“客户”和“关系过程”的“接收者”的术语应该选C beneficiary“受益者”。D token指“符号”。
转载请注明原文地址:https://www.tihaiku.com/zcyy/3276580.html
相关试题推荐
______approachthesamelinguisticunitfromdifferentperspectives.A、Syntaxan
Fromtheperspectiveoftraditionalapproachofsyntax,nounhasthecategories
Weallknowthatprogramminglanguageisthesystemofsyntax,grammar,ands
Contrasttoresearchers’expectations,dysfunctionalfamilyrelationshipsa
Contrasttoresearchers’expectations,dysfunctionalfamilyrelationshipsa
Contrasttoresearchers’expectations,dysfunctionalfamilyrelationshipsa
Contrasttoresearchers’expectations,dysfunctionalfamilyrelationshipsa
Contrasttoresearchers’expectations,dysfunctionalfamilyrelationshipsa
Syntaxisabouttheprincipleofformingcorrect______.A、morphologyB、sentences
______isproposedbyChomsky.A、langueB、functionalgrammarC、theuniversalgram
随机试题
Youdon’thavetoworryaboutmakingyourselfunderstandasmanypeopleherekno
HowcanIeverconcentrateifyou_________continually_________mewithsillyq
Thepopularnotionthatolderpeopleneedlesssleepthanyoungeradultsis
Polarbears,rhinocerosesandelephantsareallontheimmediatecriticalli
Withnoqualificationsandilleducationalbackground,Henry__________himself_
PoorpeoplehaveI.Q.’ssignificantlylowerthanthoseofrichpeople,andt
检查结果符合急性链球菌感染后肾炎,对确立诊断下列哪项检查最有价值A.双肾B超
硝酸酯类与β受体阻断药联合应用于治疗心绞痛,不正确的是()A.降低血压
已知电路如图所示,其中,相应电流I在电压源单独作用时的分量为( )。 A、
A提示:为奇函数,f(-x)=-f(x),积分区间x:[-3,3],由定积分的性质可知,奇函数在对称区间积分为零。
最新回复
(
0
)