配制2:1等张含钠液120ml需A.0.9%NaCl80ml,5%NaHC040

admin2022-08-02  9

问题 配制2:1等张含钠液120ml需A.0.9%NaCl80ml,5%NaHC040mlB.0.9%NaCl80ml,1.8%NaHCO40mlC.0.9%NaCl80ml,10%葡萄糖40mlD.0.9%NaCl40ml,5%NaHC080mlE.0.9%NaCl80ml,1.4%NaHC040ml

选项 A.0.9%NaCl80ml,5%NaHC040mlB.0.9%NaCl80ml,1.8%NaHCO40mlC.0.9%NaCl80ml,10%葡萄糖40mlD.0.9%NaCl40ml,5%NaHC080mlE.0.9%NaCl80ml,1.4%NaHC040ml

答案 E

解析 0.9%氯化钠为等张液,5%碳酸氢钠为3.5张液,1.4%碳酸氢钠为等张液。2:1等张含钠液120ml=0.9%氯化钠80ml+1.4%碳酸氢钠40ml。5%碳酸氢钠10ml+10%葡萄糖30ml=1.4%碳酸氢钠40ml。故2:1等张含钠液120ml=0.9%氯化钠80ml+5%碳酸氢钠10ml+10%葡萄糖30ml。
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