A.Z=(1-j2)Ω B.Z=(1+j2)Ω C.Y=(0.2-j0.4)

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问题 A.Z=(1-j2)ΩB.Z=(1+j2)ΩC.Y=(0.2-j0.4)SD.Y=(0.4+j0.2)S

选项 A.Z=(1-j2)Ω
B.Z=(1+j2)Ω
C.Y=(0.2-j0.4)S
D.Y=(0.4+j0.2)S

答案 A

解析
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