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[img]2014m9x/ct_egreqj_egreqbj_0031_20148[/img] [br] BIn this question you are a
[img]2014m9x/ct_egreqj_egreqbj_0031_20148[/img] [br] BIn this question you are a
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2025-02-24
29
管理
问题
[br]
选项
答案
B
解析
In this question you are asked to compare the area of a parallelogram with an area of 24, given two side lengths and the measure of one interior angle of the parallelogram. Since the measure of the interior angle given is 125°, you can conclude that the parallelogram is not a rectangle.
Recall that the area of a parallelogram is found by multiplying the length of a base by the height corresponding to the base. It is helpful to draw the vertical height from vertex C to base AD of the parallelogram, as shown in the figure below.
Note that the newly drawn height is a leg in a newly formed right triangle. The hypotenuse of the triangle is a side of the parallelogram and has length 6. Thus, the leg of the triangle, which is the height of the parallelogram, must be less than the hypotenuse 6. The area of the parallelogram is equal to the length of base AD, which is 4, times the height, which is less than 6. Since the product of 4 and a number less than 6 must be less than 24, the area of the parallelogram must be less than 24. Quantity B is greater than Quantity A, and the correct answer is Choice B.
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